Для этого есть новый фильтр lua: https://pandoc.org/lua-filters.html#counting-words-in-a-document
Сохраните следующий код как wordcount.lua
-- counts words in a document words = 0 wordcount = { Str = function(el) -- we don't count a word if it's entirely punctuation: if el.text:match("%P") then words = words + 1 end end, Code = function(el) _,n = el.text:gsub("%S+","") words = words + n end, CodeBlock = function(el) _,n = el.text:gsub("%S+","") words = words + n end } function Pandoc(el) -- skip metadata, just count body: pandoc.walk_block(pandoc.Div(el.blocks), wordcount) print(words .. " words in body") os.exit(0) end
и позвоните Пандоку так:
pandoc --lua-filter wordcount.lua myfile.md